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2x^2-22x-181.5=0
a = 2; b = -22; c = -181.5;
Δ = b2-4ac
Δ = -222-4·2·(-181.5)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-44}{2*2}=\frac{-22}{4} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+44}{2*2}=\frac{66}{4} =16+1/2 $
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